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2d_graphics [2012/08/01 01:21] – javapimp2d_graphics [2023/08/18 18:15] (current) – external edit 127.0.0.1
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 Intersection: `(2, 3)` Intersection: `(2, 3)`
  
 +a``graph width=320; height=220; xmin=-8.3; xmax=8.3; ymin=-3.3; ymax=8.3; xscl=1; yscl=1; plot(1/2*x + 2); enda``graph
 <html> <html>
-<table><tr><td> +<embed class="ASCIIsvg" script=' width=320; height=220; xmin=-8.3; xmax=8.3; ymin=-3.3; ymax=8.3; xscl=1; yscl=1; plot(1/2*x + 2); '/>
-<div class="ASCIIsvg"> +
-<embed class="ASCIIsvg" src="http://www.fourthwoods.com/js/d.svgd.svg" wmode="transparent" script=' width=320; xmin=-8.3; xmax=8.3; ymin=-3.3; ymax=8.3; xscl=1; yscl=1; plot(1/2*x + 2); '/> +
-</div> +
-</td></tr></table>+
 </html> </html>
  
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 `y = -2x + 7` `y = -2x + 7`
  
-<html> + 
-<table><tr><td> +<embed class="ASCIIsvg" src="http://www.fourthwoods.com/js/d.svg" wmode="transparent" script=' width=320; height=220; xmin=-8.3; xmax=8.3; ymin=-3.3; ymax=8.3; xscl=1; yscl=1; plot(1/2*x + 2); plot(-2x + 7);'/> 
-<div class="ASCIIsvg"> +
-<embed class="ASCIIsvg" src="http://www.fourthwoods.com/js/d.svgd.svg" wmode="transparent" script=' width=320; xmin=-8.3; xmax=8.3; ymin=-3.3; ymax=8.3; xscl=1; yscl=1; plot(1/2*x + 2); plot(-2x + 7);'/> +
-</div> +
-</td></tr></table> +
-</html>+
  
 ===== Intersection of two lines ===== ===== Intersection of two lines =====
 Two lines intersect when the point `(x, y)` satisfies both equations. To determine the point of intersection of two lines: Two lines intersect when the point `(x, y)` satisfies both equations. To determine the point of intersection of two lines:
  
-amath +`y_1 = 1/2 x_1 + 2`\\ 
-y_1 = 1/2 x_1 + 2\\ +`y_2 = -2x_2 + 7`
-y_2 = -2x_2 + 7 +
-endamath+
  
 Given that `y_1 = y_2` we can write: Given that `y_1 = y_2` we can write:
Line 77: Line 68:
  
 amath amath
-1/2 x + 2 = -2x + 7\\+1/2 x + 2 = -2x + 7 
 + 
 +Now solve for x: 
 1/2 x + 2x + 2 = 7\\ 1/2 x + 2x + 2 = 7\\
 5/2 x + 2 = 7\\ 5/2 x + 2 = 7\\
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 The point of intersection of the two lines is `(2, 3)` The point of intersection of the two lines is `(2, 3)`
 +
 +===== Find point on a line =====
 +Given a point on a line `(x, y)` a slope `m` and a distance `d` along the line from the given point, what is the `(x_1, y_1)` of the new point?
 +
 +`c = cos(theta) = 1/sqrt(1 + m^2)`\\
 +`s = sin(theta) = m/sqrt(1 + m^2)`\\
 +`x_1 = x + d * c`\\
 +`y_1 = y + d * s`
  
 ===== Pythagorean theorem ===== ===== Pythagorean theorem =====
2d_graphics.1343784100.txt.gz · Last modified: 2023/08/18 18:15 (external edit)